Sets, Relations and Functions

Sets, Relations and Functions PDF Notes, Important Questions And Synopsis

JEE Main Video Lectures By Experts

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Properties of Inverse Trigonometry Part - 1

This video explains the properties of inverse trigonometric applications and their usage in problem solving.
Trigonometric identities and problems

Fundamental trigonometric identities and problems based on them. Sign Convention of trigonometric ratios in various quadrants.
Graphical representation of inverse trigonometric functions

Graphical representation of inverse trigonometric functions and principle value of these functions.
Degree measure and Radian measure

This video explains the concept of negative & positive angles, conversion of degree measure to radian measure of angles and vice versa.
Continuous and Discontinuous function

Understand the meaning of function to be continuous and discontinuous, combine functions algebraically and study graphs.
Relationship between continuity and differentiability - Part 1

Relationship between continuity and differentiability, concept of composite functions & differentiating composite functions using the Chain Rule.

JEE Main - Maths

Q) Find the range of f(x) = x + 1/x Ans) See the image which I have uploaded.. I have just broken the eqn into √x² + 1/√x² +2 -2 ..and have formed the identity (a+b)² and the range is coming (-∞, 2 ] U [ -2, ∞ ) which is wrong.. the correct range is coming from (a-b)² which is (-∞, -2 ] U [ 2, ∞ ). My Doubt- Why (a+b)² is not giving the correct range? Request- Please send the solution using (a+b)². I've attached an image and let me know if I'm wrong somewhere or why the correct solution isn't coming by using (a+b)². Thanks, Samit Future Top 50 ranker in JEE ADVANCE