Asked by sumahr | 2nd Oct, 2009, 01:19: PM
Let's first figure out what combination can provide the 3 μF.
Connecting two capacitors in series will give the capacitance of 1 μF.
So we can connect it in parallel with another capacitor to get a equivalent capacitance of
2 μF + 1 μF = 3 μF
So we require 3 capcacitors which turns out ot be minimum, since other combinations such as two in series and such 3 series combinations in parallel will also give 3 μF, but a total of 6 capacitors will be required.
Answered by | 2nd Oct, 2009, 02:33: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number