CBSE Class 12-science Answered
obtain expression for force between plates of a charged parallel plate capacitor
Asked by bmahalik21 | 05 Mar, 2023, 08:23: PM
Expert Answer
Electric field E near capacitor plate , E = σ / ( 2 εr εo )
where σ = Q/A is surface charge density on capacitor plate. Q is total charge o plate and A is area.
εr is dielectric constant of material between capacitor plates. If capacitor plates are air filled ,then εr = 1
εo is permittivity of free space.
Hence electric field E becomes , 
Force F on charges of other plate , F= ( Q ×E )
Normally we do not measure , charge on capacitor plates .
We know the capacitance C of capacitors and applied electrical potential difference V across capacitor plates .
Q = C × V .
Hence force between capacitor plates becomes
Answered by Thiyagarajan K | 05 Mar, 2023, 10:12: PM
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