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CBSE Class 12-science Answered

obtain expression for force between plates of a charged parallel plate capacitor
Asked by bmahalik21 | 05 Mar, 2023, 08:23: PM
answered-by-expert Expert Answer
Electric field E near capacitor plate , E = σ / ( 2 εr εo )
 
where σ = Q/A  is surface charge density on capacitor plate. Q is total charge o plate and A is area.
 
εr is dielectric constant of material between capacitor plates. If capacitor plates are air filled ,then εr = 1
 
εo is permittivity of free space.
 
Hence electric field E becomes , begin mathsize 14px style E space equals space fraction numerator Q over denominator 2 space A space epsilon subscript r space epsilon subscript o end fraction end style
 
Force F on charges of other plate , F= ( Q ×E )
 
begin mathsize 14px style F space equals space fraction numerator Q squared over denominator 2 space cross times space A space cross times epsilon subscript r cross times space epsilon subscript o space end fraction end style
 
Normally we do not measure , charge on capacitor plates .
 
We know the capacitance C of capacitors and applied electrical potential difference V across capacitor plates .
 
Q = C × V .
 
Hence force between capacitor plates becomes
 
begin mathsize 14px style F space equals space fraction numerator C squared space cross times space V squared over denominator 2 space cross times space A space cross times epsilon subscript r cross times space epsilon subscript o space end fraction end style
 
Answered by Thiyagarajan K | 05 Mar, 2023, 10:12: PM

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