Calculate the capacitance of a parallel plate capacitor of each plate of which is of area 50cm^2 and and they are seperated by a dielectric slab of thickness 2mm of dielectric constant.
Asked by manandhiman023 | 13th Jun, 2022, 01:52: PM
Dielectric constant of dielectric material between parallel plates is not given.
Let us assume Dielectric constant of dielectric material between parallel plates isK
Capacitance C of parallel plate capacitor is given as
C = ( K × εo × A ) / d
where εo = 8.854 × 10-12 F/m is permittivity of free space, A = 50 cm2 is area of plate and d = 2 mm is distance between plates
C = ( K × 8.854 × 10-12 × 50 × 10-4 ) / 0.002 = K × 2.213 × 10-11 F
Capacitance C = K × 22.13 pF
( 1 pF = 10-12 F )
Answered by Thiyagarajan K | 13th Jun, 2022, 03:51: PM
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