CBSE Class 12-science Answered
how the electric field b/w parallel plate capacitor comes out to be sigma/ۥ
Asked by yashrajgharte24.12dgatl | 06 Aug, 2021, 21:02: PM
![](https://images.topperlearning.com/topper/tinymce/imagemanager/files/a7bb6b1136342daed4f9f424a1a876f3610d60903c2412.88655278f1.png)
Electric field E near infinite plane charge is given as
E = σ / ( 2 εo )
Where σ is surface charge density and εo is permittivity of free space.
In a parallel plates capacitor, plates dimension is very much greater than the separation distance.
In that case, elctric field near a parallel plate of capacitor is considered as electric field near infinite plane charge.
As shown in figure , electric field due to positive charged plane and electric field due to negatively charged
plane are in same direction.
Hence net electric field Enet is given as
Enet = E+ + E- = [ σ / ( 2 εo ) ] + [ σ / ( 2 εo ) ] = σ / εo
Answered by Thiyagarajan K | 06 Aug, 2021, 21:59: PM
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