CBSE Class 12-science Answered

Let ε_o  be the permittivity of free space , A is area of plates and d is distance between plates.

Capacitance C is

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Charge Q = C × V

where V is electrical potential difference between plates .

Q = 1.04 × 10^-11 × 650 C = 6.76 × 10^-9 C

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Electrical energy U stored in capacitor is

U = (1/2) C V² = 0.5 × 1.04 × 10^-11 × 650 × 650  = 2.197 × 10^-6 J

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Energy density E is ε_o

E = (1/2) ε_o U² = (1/2) × 8.854 × 10^-12 × ( 2.197 × 10^-6 )² = 2.137 × 10^-23 J/m³