CBSE Class 12-science Answered
An alpha particle is accelerated through a potential difference of 2000v what will be the increase in energy in electron volt
Asked by Shankaramurthy064 | 13 May, 2020, 08:47: AM
An α - particle is accelerated to PD = 2000 V
Increase in kinetic energy, Δ K = Change in Potential energy (ΔU)
Thus,
Δ K = Q V = (2e) x (2000 Volts) = 4000eV
Answered by Shiwani Sawant | 13 May, 2020, 11:57: AM
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