CBSE Class 11-science Answered
Arrange the electrons represented by the following set of
quantum number in decreasing order of energy.
(i) n = 4, l =0, m=0 S= +
(ii) n = 2, l =1, m=1 S= -
(iii) n = 3, l =2, m=0 S= +
(iv) n = 3, l =0, m=0 S= -
Asked by Neetukhaiwal | 24 Jul, 2021, 11:18: AM
Expert Answer
Order of energy is calculated by (n+l) rule. Orbital which is having lower (n+l) value will have lower energy and If values of (n+l) is same than orbital which is having lower value of n will have lower energy,
So, Decreasing order of energy-
(iii)>(i)>(iv)>(ii)
Answered by Ravi | 29 Jul, 2021, 11:10: AM
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