oxidation state
Asked by saloni | 15th Dec, 2012, 08:44: PM
Expert Answer:
Oxidation state of NItrogen in N2H4 is -2. 2(-2) + 4(+1)= 0
therefore two N makes it -4 , since they lose 10 e- , hence total charge is +6, and since H is still +1 , Two N divides the +6 .
then ox state of N is +3 in the new compound Y
Oxidation state of NItrogen in N2H4 is -2. 2(-2) + 4(+1)= 0
therefore two N makes it -4 , since they lose 10 e- , hence total charge is +6, and since H is still +1 , Two N divides the +6 .
then ox state of N is +3 in the new compound Y
Answered by | 16th Dec, 2012, 09:33: AM
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