oxidation state
Asked by saloni
| 15th Dec, 2012,
08:44: PM
Expert Answer:
Oxidation state of NItrogen in N2H4 is -2. 2(-2) + 4(+1)= 0
therefore two N makes it -4 , since they lose 10 e- , hence total charge is +6, and since H is still +1 , Two N divides the +6 .
then ox state of N is +3 in the new compound Y
Oxidation state of NItrogen in N2H4 is -2. 2(-2) + 4(+1)= 0
therefore two N makes it -4 , since they lose 10 e- , hence total charge is +6, and since H is still +1 , Two N divides the +6 .
then ox state of N is +3 in the new compound Y
Answered by
| 16th Dec, 2012,
09:33: AM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change