oxidation state

Asked by saloni | 15th Dec, 2012, 08:44: PM

Expert Answer:

Oxidation state of NItrogen in N2H4 is -2.  2(-2) + 4(+1)= 0

therefore two N makes it -4 , since they lose 10 e-  , hence total charge is +6, and since H is still +1 ,  Two N divides the +6 .

then ox state of N is +3 in the new compound Y

Answered by  | 16th Dec, 2012, 09:33: AM

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