CBSE Class 11-science Answered

The solution for the question number 114. 

The electronegativity of H = 2.2 and that of O = 3.44

The products of given reaction are H₂O₂ and H₂O

Thus, in both the products the more electronegative atom is oxygen over hydrogen.

So, we need to find out the oxidation state of oxygen in both the products.

Let us consider the oxidation state of oxygen in both the products as ‘x’.

We know that the oxidation state of hydrogen is +1.

Oxidation state of O in H₂O₂,

2(+1) + 2(x) = 0

2 + 2x = 0

x = −1

Thus, oxidation state of oxygen in H₂O₂ is ‘−1’.

Oxidation state of O in H₂O,

2(+1) + x = 0

2 + x = 0

x = −2

Thus, oxidation state of oxygen in H₂O is ‘−2’.