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114 and 115 plzzz
Asked by Kattaithihaas | 24 Jul, 2022, 06:03: PM
Dear Student,

The solution for the question number 114.

The electronegativity of H = 2.2 and that of O = 3.44

The products of given reaction are H2O2 and H2O

Thus, in both the products the more electronegative atom is oxygen over hydrogen.

So, we need to find out the oxidation state of oxygen in both the products.

Let us consider the oxidation state of oxygen in both the products as ‘x’.

We know that the oxidation state of hydrogen is +1.

Oxidation state of O in H2O2,

2(+1) + 2(x) = 0

2 + 2x = 0

x = −1

Thus, oxidation state of oxygen in H2O2 is ‘−1’.

Oxidation state of O in H2O,

2(+1) + x = 0

2 + x = 0

x = −2

Thus, oxidation state of oxygen in H2O is ‘−2’.

Hence, the correct option is option D i.e. −1, −2

Thanks and Regards
Answered by | 24 Jul, 2022, 07:16: PM

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