oxidation State of cr2o-²7

Asked by snehadethe45 | 22nd Oct, 2020, 11:31: AM

Expert Answer:

Suppose oxidation number on Cr=x
charge on dichromate ion=-2
2 x minus 2 left parenthesis 7 right parenthesis equals negative 2
2 x minus 14 equals negative 2
2 x equals negative 2 plus 14
2 x equals 12
x equals plus 6
 

Answered by Ravi | 25th Oct, 2020, 06:33: PM