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CBSE Class 11-science Answered

For the reaction, MnO4⊝+ C2O42− → MnO2+ CO2 ; The simplest mole ratio of MnO4⊝ and C2O42− in which they react is
Asked by debjit_dm | 04 May, 2020, 03:08: PM
Expert Answer
MnO subscript 4 superscript minus space space plus space straight C subscript 2 straight O subscript 4 superscript negative 2 end superscript space plus space straight H to the power of plus space rightwards arrow Mn to the power of plus 2 end exponent space plus space CO subscript 2 space plus space straight H subscript 2 straight O
Oxidation number of Mn in M n O subscript 4 superscript negative 2 end superscript
x-8=-1
x=+7
 
Change of oxidation number of Mn is from +7 to +2
The decrease in oxidation number is=7-2=5
 
Oxidation number of C increases from +3 to +4.
The change in oxidation number for 1 C atom=4-3=1
The increase in oxidation number for 2 C atom=2
 
1) To balance the oxidation number-
 
2 M n O subscript 4 superscript minus space plus space 5 C subscript 2 O subscript 4 superscript negative 2 end superscript space rightwards arrow 2 M n to the power of plus 2 end exponent space plus space 10 C O subscript 2
2) Balance the O atoms by adding 8 water molecules on product side-
 
2 MnO subscript 4 superscript minus space plus space 5 straight C subscript 2 straight O subscript 4 superscript negative 2 end superscript space rightwards arrow 2 Mn to the power of plus 2 end exponent plus 10 CO subscript 2 space plus space 8 straight H subscript 2 straight O
 
3) Balance the H atoms by adding 16 H ions to reactant side-
 
2 M n O subscript 4 superscript negative 2 end superscript space plus space 5 C subscript 2 O subscript 4 superscript negative 2 end superscript space plus space 16 H to the power of plus rightwards arrow 2 M n to the power of plus 2 end exponent space plus space 10 C O subscript 2 space plus space 8 H subscript 2 O
 
This is the  balanced equation.
 
The simples molar ratio of these reactants is 2:5.
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