Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 9 Answered

calculate the amount of work required to stop a car of 1000kg moving with speed of 72km/h
Asked by sadhanaasadhanaa67 | 04 Feb, 2024, 12:27: PM
answered-by-expert Expert Answer

72 km/hr = 72 × (5/18) m/s = 20 m/s

Let m be mass and v be velocity of car.

Kinetic energy = (1/2) m v2 = 0.5 × 1000 × 20 × 20 = 2 × 105 J

Work done to stop the vehicle = Kinetic energy of vehicle.

Work done to stop the vehicle = 2 × 105 J

Answered by Thiyagarajan K | 05 Feb, 2024, 08:40: AM
CBSE 9 - Physics
Asked by sadhanaasadhanaa67 | 04 Feb, 2024, 12:27: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by atiquzzaman100 | 21 Oct, 2021, 01:35: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by harikishortomar | 03 Jan, 2021, 10:52: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by varadaawasekar | 08 Oct, 2020, 02:16: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by Deepak | 06 Jul, 2020, 06:23: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by ashabhardwaj490 | 27 Jan, 2020, 06:17: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by kavitavinaysharma | 23 Jan, 2020, 10:05: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×