CBSE Class 11-science Physics Motion in a Straight Line
- A particle travels in a straight line, such that for a short time 2s≤t≤6s, its motion is described by v=(4/a) m/s, where a is in m/s 2 . If v =8m/s when t = 2s, determine the particle's acceleration when t = 4s.
- Distance covered by a train is 72 km with initial velocity of 20 m/s in 30 minutes. Find it's acceleration
- Derive an expression for average acceleration and instantaneous accelerationfor the motion of an object in x-y plane
- Velocity as a function of position for a particle is given as v = √x (ii) Find acceleration as function of time.
- Formula to find distance travelled by an uniformly accelerated body is
- The distance x covered by a body moving in a straight line in time t is given by the relation- 2x²+3x=t If v is the velocity of body at a certain instance of time, find it's acceleration.
- eg. v = 2x ; assume t = 0 ; x = 2 m ; find a(t)?
- Define instantaneous acceleration.
- The velocity of the particle is given by v = 4t2 + 7 cm/s. Find the velocity of the particle during the time interval t1 = 2s and t2 = 4s also find the average acceleration during the same interval of time.
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