What volume is needed to store 0.050 moles of helium gas at 202.6 kPa and 127ºC?

Asked by Topperlearning User | 20th Apr, 2015, 11:17: AM

Expert Answer:

We know that, PV = nRT

P = 202.6 kPa

n = 0.050 mol

T = 127 + 273 = 400K

V = ? L

R = 8.314 J K-1 mol-1

202.6 x V = 0.050 x 8.314 x 400

202.6 V = 166.28

begin mathsize 11px style straight V space equals space fraction numerator 166.28 over denominator 202.6 end fraction end style

V = 0.821 L or 821 mL

Answered by  | 20th Apr, 2015, 01:17: PM