at 25 degree celsius and 0.993 bar, 135 ml of a gas is collected over water. if the gas weighs 0.16g and the aqueous tension at 25 degree celsius , is 0.0317. calculate the molar mass of the gas.

Asked by Ankit | 16th Mar, 2019, 01:01: PM

Expert Answer:

Given
 
P  = 0.993 - 0.0317
   = 0.9613  bar
 
  = 0.9487 atm
 
T = 25 0C
 
V =135 ml
 
 
We space have comma

PV equals space nRT

No. space of space moles space equals fraction numerator Mass space of space gas over denominator Molar space mass space of space gas end fraction

PV thin space space equals straight w over straight m RT

0.9487 cross times 135 space equals fraction numerator 0.16 over denominator straight m end fraction space open parentheses 0.0821 cross times 298 close parentheses space

space space space space space space space space space space space space space space space space space space space straight m space equals fraction numerator 0.16 cross times 298 cross times 0.0821 over denominator 0.9487 cross times 0.135 end fraction

space space space space space space space space space space space space space space space space space space space straight m space equals space fraction numerator 3.914 over denominator 0.12 end fraction
space space space space space space space space space space space space space space space space space
Molar space mass space of space gas space equals space 32.61 space mol divided by gm
 

Answered by Varsha | 16th Mar, 2019, 06:51: PM