CBSE Class 11-science Answered
3rd?
![question image](https://images.topperlearning.com/topper/new-ate/428329386462177115NewDoc201808041.jpg)
Asked by smanishkumar2002 | 04 Aug, 2018, 05:36: AM
Given:
Volume: 1 litre
Temperature: 0°C = 273 K
![](https://images.topperlearning.com/topper/tinymce/cache/b6e492c28ce03e5b4c925c38f0b87959.png)
![Solution colon
Lets space find space the space partial space pressure space of space straight O subscript 2 space and space straight H subscript 2
Partial space pressure space of space straight O subscript 2 colon
No. space of space moles space equals 4 over 32 equals space 0.125 space moles
straight P subscript 1 equals nRT over straight V space equals space fraction numerator 0.125 space cross times 0.082 cross times 273 over denominator 1 end fraction equals space 2.80 space atm
Partial space pressure space of space straight H subscript 2 colon
No. space of space moles space equals 2 over 2 equals 1 space mole
straight P subscript 2 equals nRT over straight V space equals space fraction numerator 1 space cross times 0.082 cross times 273 over denominator 1 end fraction equals space 22.386 space atm
Now comma space Total space pressureof space mixture space equals 2.80 space plus space 22.386 space equals space 25.18 space atm](https://images.topperlearning.com/topper/tinymce/cache/e7952303735eac0d7b9cd6e82e0cd7a3.png)
Answered by Ramandeep | 04 Aug, 2018, 22:23: PM
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