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CBSE Class 11-science Answered

3rd?
Asked by smanishkumar2002 | 04 Aug, 2018, 05:36: AM
Expert Answer
Given:
Volume: 1 litre
Temperature: 0°C = 273 K
 
Solution colon Lets space find space the space partial space pressure space of space straight O subscript 2 space and space straight H subscript 2 Partial space pressure space of space straight O subscript 2 colon No. space of space moles space equals 4 over 32 equals space 0.125 space moles straight P subscript 1 equals nRT over straight V space equals space fraction numerator 0.125 space cross times 0.082 cross times 273 over denominator 1 end fraction equals space 2.80 space atm Partial space pressure space of space straight H subscript 2 colon No. space of space moles space equals 2 over 2 equals 1 space mole straight P subscript 2 equals nRT over straight V space equals space fraction numerator 1 space cross times 0.082 cross times 273 over denominator 1 end fraction equals space 22.386 space atm Now comma space Total space pressureof space mixture space equals 2.80 space plus space 22.386 space equals space 25.18 space atm
Answered by Ramandeep | 04 Aug, 2018, 10:23: PM

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CBSE 11-science - Chemistry
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