At what pressure would 0.450 mole of nitrogen gas at 23.0 °C occupy 8.90 L?

Asked by Topperlearning User | 20th Apr, 2015, 11:33: AM

Expert Answer:

begin mathsize 11px style straight P space equals space fraction numerator nRT space over denominator straight V end fraction end style

P =?

V = 8.90 L

n = 0.450 mol

R = 0.0821 L atm mol-1 K-1

T = 23 + 273 = 296 K

begin mathsize 11px style therefore space straight P space equals space fraction numerator left square bracket left parenthesis 0.450 space mol right parenthesis space left parenthesis 0.0821 space straight L space atm space mol to the power of negative 1 end exponent space straight K to the power of negative 1 end exponent right parenthesis space left parenthesis 296.0 space straight K right parenthesis right square bracket space over denominator space 8.90 space straight L space end fraction
therefore space straight P space equals 1.23 space atm end style

Answered by  | 20th Apr, 2015, 01:33: PM