The motion of a particle executing simple harmonic motion is described by the displacement function, x (t) = A cos (?t + ?). If the initial (t = 0) position of the particle is 1 cm and its initial velocity is ? cm/s, what are its amplitude and initial phase angle? The angular frequency of the particle is ? /s. If instead of the cosine function, we choose the sine function to describe the SHM: x = B sin (?t + ?), what are the amplitude and initial phase of the particle with the above initial conditions?

Asked by SHRAWANI SHEKHAR | 11th Feb, 2014, 08:02: PM

Expert Answer:

Answered by  | 12th Feb, 2014, 10:58: AM

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