A small body of mass 0.10kg is undergoing simple harmonic motion of simplitude 1.0 meter and period of 0.20 sec the maximum value of the force acting on it
Asked by devvratagrahari | 2nd Dec, 2019, 06:44: AM
The value of maximum force is, Fmax = mamax ... (1)
We know, amax = Aω2
Now, T = 2∏/ω
→ω = 2∏/T
Substituting in (1), we get,
Fmax = m A(2∏/T)2
Fmax = 0.1×1 × [(2 × 3.14)/0.2]2 = 98.596 N
Answered by Shiwani Sawant | 2nd Dec, 2019, 03:22: PM
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