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CBSE Class 11-science Answered

A small body of mass 0.10kg is undergoing simple harmonic motion of simplitude 1.0 meter and period of 0.20 sec the maximum value of the force acting on it

Asked by devvratagrahari | 02 Dec, 2019, 06:44: AM
Expert Answer
The value of maximum force is, Fmax = mamax ... (1)
We know, amax = Aω2 
Now, T = 2∏/ω
→ω = 2∏/T 
 
Substituting in (1), we get, 
Fmax = m A(2∏/T)2 
Thus, 
Fmax = 0.1×1 × [(2 × 3.14)/0.2]2 = 98.596 N
 
 
Answered by Shiwani Sawant | 02 Dec, 2019, 03:22: PM
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