CBSE Class 11-science Answered
the time period of simple pendulum is 2 second it can go from equilium position at the maximum distance of 5 cm if at the start of the motion the pendulum in the position of maximum displacement towards the right of equilium position then write the different equation.
Asked by goludada1479 | 06 Feb, 2024, 07:35: PM
Expert Answer
Let the equation of displacement x as a function of time t is
.....................................(1)
where A = 5 cm is amplitude ( magnitude of maximum displacement ) , ω is angular frequency
and is initial phase .
Angular frequency ω = (2π)/T , where T = 2 s is period of oscillation of pendulam .
ω = (2π)/2 rad/s = π rad/s
It is given that at time t = 0 , bob of pendulam is at x = 5 cm , i.e, at extreme right side of equilibrium position .
Hence if we substitute t = 0 , amplitude A = 5 cm and ω = π rad/s in eqn(1) , then we get
5 = 5 cos() or = 0
the equation of displacement x as a function of time t is
x(t) = ( 5 cm ) cos(π t )
Answered by Thiyagarajan K | 08 Feb, 2024, 01:23: PM
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