CBSE Class 11-science Answered
the external diameter of test tube weighing 5g is 2cm.15g of merceury are poured into the tube so that it floats verticall in water.If tube is depressed veetically through a small distance and then released. determine the period of oscillation.g=980cm/s.
Asked by | 14 Apr, 2013, 01:00: PM
Expert Answer
so weight of 20 gm of mercury tube =Bouyant force= pi (2/100)2xl x1xg.....where l=length of tube
20g=pi (2/100)2xl x1xg
l can be found from here.
.If tube is depressed veetically through a small distance and then released. determine the period of oscillation=2pi?l/g...putting value of l can find out T.
Answered by | 15 Apr, 2013, 03:21: PM
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