the external diameter of test tube weighing 5g is 2cm.15g of merceury are poured into the tube so that it floats verticall in water.If tube is depressed veetically through a small distance and then released. determine the period of oscillation.g=980cm/s.

Asked by  | 14th Apr, 2013, 01:00: PM

Expert Answer:

so weight of 20 gm of mercury tube =Bouyant force= pi (2/100)2xl x1xg.....where l=length of tube
20g=pi (2/100)2xl x1xg
l can be found from here.
 
.If tube is depressed veetically through a small distance and then released. determine the period of oscillation=2pi?l/g...putting value of l can find out T.
 

Answered by  | 15th Apr, 2013, 03:21: PM

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