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CBSE Class 11-science Answered

Reduce the equation 4x + 3y – 9 = 0 to the normal form and find their length of perpendicular from origin to the line
Asked by Topperlearning User | 20 Oct, 2016, 06:34: AM
Expert Answer

T h e space e q u a t i o n space o f space l i n e space space 4 x plus 3 y minus 9 equals 0 C o m p a r i n g space w i t h space space x cos alpha plus y sin alpha equals p comma space w e space g e t fraction numerator cos alpha over denominator 4 end fraction equals fraction numerator sin alpha over denominator 3 end fraction equals p over 9 rightwards double arrow cos alpha equals fraction numerator 4 p over denominator 9 end fraction space a n d space sin alpha equals fraction numerator 3 p over denominator 9 end fraction space rightwards double arrow cos squared alpha plus sin squared alpha equals fraction numerator 16 p squared over denominator 9 squared end fraction plus fraction numerator 9 p squared over denominator 9 squared end fraction equals fraction numerator 25 p squared over denominator 9 squared end fraction rightwards double arrow 1 equals fraction numerator 25 p squared over denominator 9 squared end fraction rightwards double arrow p equals 9 over 5 N o r m a l space F o r m equals fraction numerator 4 x over denominator 5 end fraction plus fraction numerator 3 y over denominator 5 end fraction equals 9 over 5

Answered by | 20 Oct, 2016, 08:34: AM

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