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CBSE Class 11-science Answered

Find the distance between the parallel lines 3x + 5y + 13 = 0 and 3x + 5y – 24 = 0.
Asked by Topperlearning User | 20 Oct, 2016, 06:32: AM
Expert Answer

Given lines are 3x + 5y + 13 = 0 and 3x+5y-24=0

T h e space d i s tan c e space b e t w e e n space p a r a l l e l space l i n e s space i s space g i v e n space b y space open vertical bar fraction numerator C subscript 1 minus C subscript 2 over denominator square root of A squared plus B squared end root end fraction close vertical bar
I n space t h e space g i v e n space q u e s t i o n space A equals 3 comma B equals 5 comma space C subscript 1 equals 13 comma space C subscript 2 equals negative 24
D i s tan c e equals open vertical bar fraction numerator 13 plus 24 over denominator square root of 3 squared plus 5 squared end root end fraction close vertical bar equals fraction numerator 37 over denominator square root of 34 end fraction

 
 
Therefore, the distance is fraction numerator 37 over denominator square root of 34 end fraction units
Answered by | 20 Oct, 2016, 08:32: AM
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