CBSE Class 11-science Answered
Find the distance of the point (2, 5) from the line 4 (x + 5) = 7 (2y - 3).
Asked by Topperlearning User | 29 Apr, 2014, 03:09: PM
Expert Answer
The given line is
4 (x + 5) = 7 (2y - 3)
4x + 20 = 14y - 21
4x - 14y + 20 + 21 = 0
4x - 14y + 41 = 0
The perpendicular distance from (x1, y1) to the line ax + by + c = 0 is
.
The point (x1, y1) is (2, 5).
Perpendicular distance from (2, 5) to the line 4x - 14y + 41 = 0 is
Answered by | 29 Apr, 2014, 05:09: PM
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