Request a call back

Find the distance of the point (2, 5) from the line 4 (x + 5) = 7 (2y - 3).
Asked by Topperlearning User | 29 Apr, 2014, 03:09: PM Expert Answer

The given line is

4 (x + 5) = 7 (2y - 3) 4x + 20 = 14y - 21 4x - 14y + 20 + 21 = 0 4x - 14y + 41 = 0
The perpendicular distance from (x1, y1) to the line ax + by + c = 0 is .

The point (x1, y1) is (2, 5).

Perpendicular distance from (2, 5) to the line 4x - 14y + 41 = 0 is Answered by | 29 Apr, 2014, 05:09: PM

## Concept Videos

CBSE 11-science - Maths
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by Topperlearning User | 20 Oct, 2016, 06:34: AM ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by Topperlearning User | 29 Apr, 2014, 03:09: PM ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by Topperlearning User | 20 Oct, 2016, 06:32: AM ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by Topperlearning User | 28 Apr, 2014, 08:04: AM ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by Topperlearning User | 30 Apr, 2014, 09:00: AM ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by Topperlearning User | 30 Apr, 2014, 09:03: AM ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by Topperlearning User | 30 Apr, 2014, 09:08: AM ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by Topperlearning User | 20 Oct, 2016, 06:26: AM ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by Topperlearning User | 20 Oct, 2016, 06:20: AM ANSWERED BY EXPERT