Request a call back

Q. Find the current drawn from the battery by the network of 4 resistors shown in the diagram. Kindly Refer the file uploaded for diagram.
Asked by Trisha Gupta | 09 Jun, 2021, 17:56: PM

### Resistance of the upper branch FCE are in series.So, equivalent resistance in the branch FCE= R1 = 10 Ω + 10 Ω = 20 ΩResistance of lower branch FDE are in seriesSo, equivalent resistance in the branch FDE = R2 = 10 Ω + 10 Ω = 20 ΩThe two resistance R1 and R2 are parallel to each other.If R is the equvalent resistance of network, thenor R = 10 ΩCurrent, V = IR

Answered by Shiwani Sawant | 09 Jun, 2021, 21:34: PM

## Application Videos

CBSE 10 - Physics
Asked by sakshikatewa0 | 08 Feb, 2024, 12:48: PM
CBSE 10 - Physics
Asked by kamalaranjanmohantymohanty5 | 06 Jan, 2024, 10:05: AM
CBSE 10 - Physics
Asked by nandhikasugumar | 05 Oct, 2023, 16:01: PM
CBSE 10 - Physics
Asked by daniya062008 | 02 Oct, 2023, 20:25: PM
CBSE 10 - Physics
Asked by prassanna.j | 03 Sep, 2023, 12:28: PM
CBSE 10 - Physics
Asked by prassanna.j | 03 Sep, 2023, 12:21: PM