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finding the net resistance
Asked by daniya062008 | 02 Oct, 2023, 08:25: PM
Case (a)

Resistors of resitances 1Ω and 2Ω are connected in series . This series combination is connected in parallel to 1.5Ω resistor.

Equivalent resistance of series combination of 1Ω and 2Ω is 3Ω .

Then equivalent resistance of 3Ω resistor  connected parallel to 1.5 Ω  is

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Case (b)

Resistors of resistances 3 Ω and 2 Ω above diagonal line AB are in series . Equivalent resistance of this series combination is 5Ω.

Similarly , Resistors of resistances 3 Ω and 2 Ω below diagonal line AB are in series . Equivalent resistance of this series combination is 5Ω.

Hence 5 Ω resistance above diagonal AB,  5 Ω resistance below diaonal AB and 1 Ω resistance in the diagonal line AB all are connected in parallel.

Equivalent resistance of network given in case (b) is

Answered by Thiyagarajan K | 02 Oct, 2023, 09:45: PM

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