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find the new resistance of wire length l area of cross section A if it is folded 4 times
Asked by nandhikasugumar | 05 Oct, 2023, 16:01: PM
answered-by-expert Expert Answer
Let R be the initial resistance . After folding the wire by 4 fold , each wire has resistance R/4 because resistance is proportional to length.
 
Then equivalent resistance of four segments when they are parallel is
 
begin mathsize 14px style 1 over R subscript e q end subscript equals fraction numerator 1 over denominator R divided by 4 end fraction plus fraction numerator 1 over denominator R divided by 4 end fraction plus fraction numerator 1 over denominator R divided by 4 end fraction plus fraction numerator 1 over denominator R divided by 4 end fraction space equals space 16 over R end style
 
Hence , equivalent resistance is R/16 , i.e initial resistance is decreased by a factor 1/16
Answered by Thiyagarajan K | 05 Oct, 2023, 17:42: PM

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