Please explain
Asked by | 21st Mar, 2009, 11:08: AM
In all the cases where β+ decay is allowed energetically (and the proton is a part of a nucleus with electron shells), it is accompanied by the electron capture process, when an atomic electron is captured by a nucleus with the emission of a neutrino:
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energy + p+ + e− → n0 + νe
But if the energy difference between initial and final states is low (less than 2mec2), then β+ decay is not energetically possible, and electron capture is the sole decay mode.
Answered by | 28th Mar, 2009, 06:22: PM
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