Nuclear density of hydrogen is 2.3x1017 kg/m3. Given A = 56 for iron, find its nuclear density
Asked by gaurish6247 | 7th Apr, 2021, 05:16: PM
Radius of Hydrogen nucleus, RH = Ro A1/3 = Ro
Where A is Mass number
Radius of Fe nucleus RFe = Ro 561/3
Density of hydrogen nuclei , = mass / volume = mH / [ (4/3)π RH3 ]
Density of Fe nuclei , = mFe / [ (4/3)π RFe3 ]
Density of Fe nucleus and Density of Hydrogen nucleus are same
= = 2.3 × 1017 kg/m3
Answered by Thiyagarajan K | 7th Apr, 2021, 10:11: PM
- the atomic masses of two different nuclei are 3 and 81 then the ratio of their radius r
- WHAT ARE ISOTONES AND ISOTOPES CORRECT DEFINITION?
- claculate the energy equivalent of 1 g of substance.
- In scattering experiment, find the distance of closest approach, if a 6 MeV alpha particle is used?
- A neutron collide with hydrogen atom then what will happen
- What is meant by Atomic Nucleus?
- What do you mean by nuclear size?
- What is nuclear density?
- What do you mean by isotopes?
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number