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Nuclear density of hydrogen is 2.3x1017 kg/m3. Given A = 56 for iron, find its nuclear density
Asked by gaurish6247 | 07 Apr, 2021, 05:16: PM
Radius of Hydrogen  nucleus, RH = Ro A1/3 = Ro

Where A is Mass number

Radius of Fe nucleus  RFe = Ro 561/3

Density of hydrogen nuclei ,  = mass / volume =  mH / [ (4/3)π RH3 ]

Density of Fe nuclei , = mFe / [ (4/3)π RFe3 ]

Density of Fe nucleus and Density of Hydrogen nucleus are same

= = 2.3 × 1017 kg/m3
Answered by Thiyagarajan K | 07 Apr, 2021, 10:11: PM

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