Nuclear density of hydrogen is 2.3x1017 kg/m3. Given A = 56 for iron, find its nuclear density
Asked by gaurish6247 | 7th Apr, 2021, 05:16: PM
Expert Answer:
Radius of Hydrogen nucleus, RH = Ro A1/3 = Ro
Where A is Mass number
Radius of Fe nucleus RFe = Ro 561/3
Density of hydrogen nuclei , 
= mass / volume = mH / [ (4/3)π RH3 ]
Density of Fe nuclei , 
= mFe / [ (4/3)π RFe3 ]
Density of Fe nucleus and Density of Hydrogen nucleus are same
= = 2.3 × 1017 kg/m3
= mass / volume = mH / [ (4/3)π RH3 ] = mFe / [ (4/3)π RFe3 ] = = 2.3 × 1017 kg/m3Answered by Thiyagarajan K | 7th Apr, 2021, 10:11: PM
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