CBSE Class 12-science Answered
. A nucleus of mass number 240 and having binding energy/nucleon 7.6 MeV splits into two fragments Y, Z of mass numbers 110 and 130 respectively. If the binding energy/nucleon of Y, Z is equal to 8.5 MeV each, calculate the energy released in the nuclear reaction.
Asked by kailasks2007 | 28 Dec, 2023, 20:14: PM
Expert Answer
Initial mass number of nucleus is 240
Sum of mass numbers of fragments after fission = (130+110 ) = 240
Initial binding energy per nucleon = 7.6 MeV
binding energy per nucleon of fragments = 8.5 MeV
Hence energy released in fission = (8.5 -7.6) × 240 MeV = 216 MeV
Answered by Thiyagarajan K | 28 Dec, 2023, 22:04: PM
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