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. A nucleus of mass number 240 and having binding energy/nucleon 7.6 MeV splits into two fragments Y, Z of mass numbers 110 and 130 respectively. If the binding energy/nucleon of Y, Z is equal to 8.5 MeV each, calculate the energy released in the nuclear reaction.

Initial mass number of nucleus is 240

Sum of mass numbers of fragments after fission =  (130+110 ) = 240

Initial binding energy per nucleon = 7.6 MeV

binding energy per nucleon of fragments = 8.5 MeV

Hence energy released in fission = (8.5 -7.6) × 240 MeV = 216 MeV

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