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  A neutron is absorbed by a 3 LSyntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '. nucleus with subsequent emission of Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '. - particle Write the corresponding nuclear reaction. Calculate the energy released in this reaction. Given mass of 3 LSyntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '. = 6.015126 a.m.u. Mass of 2Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '.e = 4.000 26044 a.m.u. Mass of neutron begin mathsize 14px style open parentheses blank subscript 0 straight n with 1 on top close parentheses end style = 1.0086654 a.m.u. Mass of tritium Syntax error from line 1 column 58 to line 1 column 82. Unexpected '<mstyle '. = 3.016049 a.m.u.  
Asked by Topperlearning User | 02 Jun, 2015, 10:23: AM
Expert Answer

Nuclear reaction is given by

begin mathsize 14px style n presubscript 0 superscript 1 space plus space L presubscript 3 i to the power of 6 space rightwards arrow H presubscript 2 straight e to the power of 4 space plus space scriptbase straight H with 3 on top end scriptbase presubscript 1 end style

Mass of reactants = m begin mathsize 14px style open parentheses scriptbase straight n with 1 on top end scriptbase presubscript 0 close parentheses plus straight m space open parentheses scriptbase straight L with 6 on top end scriptbase presubscript 3 straight i close parentheses end style

= 1.0086654 + 6.015126 = 7.0237914 a.m.u.

Mass Defect, Δm = mass of reactant - mass of product.

Δm = 7.0237194 - 7.0186534

Δm = 0.005138 a.m.u.

Since1. a.m.u. = 931 MeV

therefore Energy released =Δm x 931 MeV

E = 0.005138 x 931

E = 4.783MeV

 

Answered by | 02 Jun, 2015, 12:23: PM
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