CBSE Class 12-science Answered
A neutron is absorbed by a 3 L
nucleus with subsequent emission of
- particle Write the corresponding nuclear reaction. Calculate the energy released in this reaction.
Given mass of 3 L
= 6.015126 a.m.u.
Mass of 2
e = 4.000 26044 a.m.u.
Mass of neutron
= 1.0086654 a.m.u.
Mass of tritium
= 3.016049 a.m.u.
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Asked by Topperlearning User | 02 Jun, 2015, 10:23: AM
Nuclear reaction is given by
Mass of reactants = m
= 1.0086654 + 6.015126 = 7.0237914 a.m.u.
Mass Defect, Δm = mass of reactant - mass of product.
Δm = 7.0237194 - 7.0186534
Δm = 0.005138 a.m.u.
Since1. a.m.u. = 931 MeV
Energy released =Δm x 931 MeV
E = 0.005138 x 931
E = 4.783MeV |
Answered by | 02 Jun, 2015, 12:23: PM
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