CBSE Class 12-science Answered
nuclei
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Asked by murshidibrahimkk | 08 Feb, 2024, 10:28: AM
if binding energy per nucleon is 7.6 MeV for unfragmented nucleus of mass number 240 ,
then total binding energy BE of unfragmented nucleus is
(BE)o = 240 × 7.6 MeV = 1824 MeV
if binding energy per nucleon is 8.5 MeV for fragmented nuclei each has equal mass number 120 ,
then total binding energy of fragments is (BE)1 = 2 × 120 × 8.5 MeV = 2040 MeV
Gain of binding energy = (BE)1 - (BE)o = ( 2040 - 1824 ) MeV = 216 MeV
Answered by Thiyagarajan K | 08 Feb, 2024, 14:57: PM
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