CBSE Class 12-science Answered
nuclei
Asked by murshidibrahimkk | 08 Feb, 2024, 10:28: AM
Expert Answer
if binding energy per nucleon is 7.6 MeV for unfragmented nucleus of mass number 240 ,
then total binding energy BE of unfragmented nucleus is
(BE)o = 240 × 7.6 MeV = 1824 MeV
if binding energy per nucleon is 8.5 MeV for fragmented nuclei each has equal mass number 120 ,
then total binding energy of fragments is (BE)1 = 2 × 120 × 8.5 MeV = 2040 MeV
Gain of binding energy = (BE)1 - (BE)o = ( 2040 - 1824 ) MeV = 216 MeV
Answered by Thiyagarajan K | 08 Feb, 2024, 02:57: PM
CBSE 12-science - Physics
Asked by murshidibrahimkk | 08 Feb, 2024, 10:28: AM
ANSWERED BY EXPERTCBSE 12-science - Physics
Asked by kailasks2007 | 28 Dec, 2023, 08:14: PM
ANSWERED BY EXPERTCBSE 12-science - Physics
Asked by varma.renu9481 | 06 Mar, 2023, 05:44: PM
ANSWERED BY EXPERTCBSE 12-science - Physics
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERTCBSE 12-science - Physics
Asked by Topperlearning User | 02 Jun, 2015, 01:03: PM
ANSWERED BY EXPERTCBSE 12-science - Physics
nucleus with subsequent emission of 
- particle Write the corresponding nuclear reaction. Calculate the energy released in this reaction.
Given mass of 3 L
e = 4.000 26044 a.m.u.
Mass of neutron 
= 1.0086654 a.m.u.
Mass of tritium 
= 3.016049 a.m.u.
Asked by Topperlearning User | 02 Jun, 2015, 10:23: AM
ANSWERED BY EXPERTCBSE 12-science - Physics
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERTCBSE 12-science - Physics
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERTCBSE 12-science - Physics
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERTCBSE 12-science - Physics
undergoes β- decay and becomes 
, Calculate the maximum kinetic energy of electrons emitted assuming that the daughter nucleus and anti- neutrino carry negligible kinetic energy.
Asked by Topperlearning User | 09 Jul, 2014, 12:48: PM
ANSWERED BY EXPERT
