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CBSE Class 12-science Answered

how are we supposed to solve this question
Asked by merinlijo_20002 | 17 Jun, 2020, 10:05: AM
Expert Answer
The half life of At-215 is 100 microseconds.The activity of sample if it contains 215mg initially is
A c t i v i t y equals fraction numerator 0.693 N over denominator t subscript begin display style bevelled 1 half end style end subscript end fraction
F i r s t space w e space h a v e space t o space c a l c u l a t e space t h e space N
N equals fraction numerator 215 cross times 10 to the power of negative 3 end exponent over denominator 215 g divided by m o l end fraction cross times 6.02 cross times 10 to the power of 23
N equals 6.02 cross times 10 to the power of 20
A c t i v i t y equals fraction numerator 0.693 cross times 6.02 cross times 10 to the power of 20 over denominator 100 cross times 10 to the power of negative 6 end exponent end fraction
A c t i v i t y equals fraction numerator 0.693 cross times 6.02 cross times 10 to the power of 20 over denominator 100 cross times 10 to the power of negative 6 end exponent end fraction
A c t i v i t y equals 4.18 cross times 10 to the power of 24
Answered by Utkarsh Lokhande | 17 Jun, 2020, 11:02: AM
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