calculate mass defect ,binding energy and binding energy per nucleon for a lithium nucleus taking it mass 7amu.
Asked by Mukesh Kumar Mahto | 2nd Nov, 2010, 12:00: AM
You may use following information and equations to calculate the mass defect, binding energy and binding energy per nucleon for lithium, taking its mass as 7 amu.
The actual mass of a nucleus is always found to be less than the sum of the masses of the nucleons present in it . The mass difference is known as the mass defect and is denoted by .
Consider nucleus of an element ZXA with the mass number 'A' and atomic number 'z' . This element contains 'z' protons and ( A - z ) neutrons . Hence , mass of the constituent nucleons ( M' ) .
( M' ) = z mp + ( A - z ) mn ------------> (1)
Where mp and mn are the masses of the proton and neutron respectively .
If 'M' is the actual mass of the nucleus of the element then the mass defect is
m = [ zmp + (A - z)mn ] - m
Answered by | 13th Dec, 2010, 02:33: PM
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