calculate mass defect ,binding energy and binding energy per nucleon for a lithium nucleus taking it mass 7amu.

Dear student

You may use following information and equations to calculate the mass defect, binding energy and binding energy per nucleon for lithium, taking its mass as 7 amu.

The actual mass of a nucleus is always found to be less than the sum of the masses of the nucleons present in it . The mass difference is known as the mass defect and is denoted by  .

Consider nucleus of an element  _ZX^A with the mass number 'A' and atomic number 'z' . This element contains 'z' protons and ( A - z ) neutrons . Hence , mass of the constituent nucleons ( M' )  .

( M' )  =  z m_p  +  ( A - z ) m_n       ------------> (1)

Where m_p  and  m_n are the masses of the proton and neutron respectively .

If 'M' is the actual mass of the nucleus of the element then the mass defect is  

m   =   [ zm_p +  (A - z)m_n ]  -  m        

 

Binding energy B.E  =      931.5  MeV 

B.E./ nucleon = B.E. / mass no.

     

We hope this clarifies your doubt.

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