Ask a Doubt
Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 10 Answered

Amar gives Rs 9000 to some athletes of a school as scholarship every month. Had there been 20 more athletes each would have got Rs 160 less. Form a pair of linear equations for this.
Asked by ayush | 24 Jul, 2013, 11:29: AM
answered-by-expert Expert Answer
This question is based on quadratic equations.
 
 
Let x = original number of athletes

9000/x - 160 = 9000/(x + 20)

(9000 - 160x)/x = 9000/(x + 20)

(9000 - 160x)(20 + x) = 9000x

180000 - 3200x + 9000x - 160x^2 - 9000x = 0

-160x^2 - 3200x + 180000 = 0

-160(x^2 + 20x - 1125) = 0

160(x + 45)(x - 25) = 0
 
Neglecting negative value, we get x = 25
Answered by | 25 Jul, 2013, 10:24: AM

Application Videos

Concept Videos

Multiple Choice Questions Practice Test
Answered Unanswered My Questions My Answers
CBSE 10 - Maths
3x-5y-4=0...9x=2y+7
question image
Asked by laxman44verma | 01 May, 2024, 09:46: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
2/x+2/3y=1/6; 3/x+2/y=0
Asked by aditikaldate7 | 21 Apr, 2024, 03:16: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
from the pair of linear equations in the following problems and find their solution graphically 10 students of class 10 to part in a mathematic quiz if the number of girls is for more than the number of boys find the number of boys and girls who took part in the quiz
Asked by muttenenimalleswarrao | 29 Mar, 2024, 08:32: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
The value of 'x' and 'y' when x+y=6 and x-y=10 a) (8,-2) b) (-2,8) c) (8,2) d) (2,8)
Asked by suvarnam458 | 23 Feb, 2024, 06:18: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Present age of 'A' is 4 years less than that of 'B'. Age of 'C', 4 years hence from now will be 60% more than the age of 'B', 4 years ago from now. Find the present average age of 'A' and 'B' together if the sum of present age of 'A' and 'C' is 48 years.
Asked by jhajuhi19 | 01 Feb, 2024, 08:43: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Data given below is related to daily routine [study time (in hours), entertainment time (in hours) and rest time (in hours)] of three students A, B and C.    Daily routine (24 hours) = Study time + Entertainment time + Rest time   A's study time is 1 hour less than B's study time and A's rest time is 7 hours more than his entertainment time. Ratio of A's entertainment time to B's entertainment time is 1: 2. Average of study time of A, B and C is 6 hours. Average of rest time of A and B is 9 hours. Ratio of C's entertainment time to his rest time is 4: 3.   If B's study and entertainment time is m% more than C's study and entertainment time together, then find that B's study and entertainment time together is what percent more than A's study and entertainment time together?
question image
Asked by jhajuhi19 | 31 Jan, 2024, 11:21: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
find the zero of 2x+3 graphically
Asked by imalakondarayudu1 | 30 Jan, 2024, 06:43: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
If 8x+5y=9&mx+10y=15 are an inconsistent pair of linear equations, then the value of m is
Asked by sbalmeeri | 29 Jan, 2024, 07:19: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
the numerator of fractions is 4 less than the denominator. if the numerator is decreased by 2 and the denominator is increased by 1 , then the denominator is 8 times the numerator. find the fraction.
Asked by am.mansi628 | 29 Nov, 2023, 05:38: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
10 students of class 10 took part in a mathematics quiz . if the number of girls is 4 more than the number of boys then ,find find the numbers of boys and number of girls who took part in the quiz
Asked by jaanooru | 13 Oct, 2023, 10:23: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
My Class Videos Tests ₹ Plans Ask a Doubt
Get Latest Study Material for Academic year 24-25 Click here
×