A uniform circular disc of mass 12 kg is held by 2 identical springs when disc is pressed down slightly and released it executes shm with time period of2 s the force constant of each spring is [2 spring in parallel]n/

Asked by SELVA | 6th Jul, 2019, 03:25: PM

Expert Answer:

when two springs are connected in parallel, the effective force constant is given by
K subscript e f f end subscript equals K subscript 1 plus K subscript 2
K subscript 1 equals K subscript 2 equals K
K subscript e f f end subscript equals 2 K
T h e space t i m e space p e r i o d space i s space g i v e n space b y
T equals 2 pi square root of m over K subscript e f f end subscript end root
s u b s t i t u t i n g space t h e space v a l u e s space w e space g e t
2 equals 2 pi square root of fraction numerator 12 over denominator 2 K end fraction end root
open parentheses 1 over pi close parentheses squared equals fraction numerator 12 over denominator 2 K end fraction
K equals 6 pi squared
K equals 59.15 N divided by m

Answered by Utkarsh Lokhande | 6th Jul, 2019, 07:55: PM