5 moles of an idealgas expands isothermally from a pressure of 10atm to 2atm at 300k.What is the largest mass which can be lifted through a height of 1m in this expansion ? plzz explain the answer in detail
Asked by TVISHA Bhatt | 10th Aug, 2014, 06:12: PM
Expert Answer:
Solution:
Work done is given by,
w= -nRT ln (p1/p2)
= -5 mol (8.314 JK-1 mol-1)(300K) ln(10atm/2atm)
= -20.075x103J
Let M be the mass which can be lifted through a height of 1m.
Work done in lifting the mass = Mgh= M x 9.81ms-2 x 1m
M X 9.81 X 1 X m2s-2 = 20.075 x 103J
M = 2046 kg
Work done is given by,
w= -nRT ln (p1/p2)
= -5 mol (8.314 JK-1 mol-1)(300K) ln(10atm/2atm)
= -20.075x103J
Let M be the mass which can be lifted through a height of 1m.
Work done in lifting the mass = Mgh= M x 9.81ms-2 x 1m
M X 9.81 X 1 X m2s-2 = 20.075 x 103J
M = 2046 kg
Answered by Vaibhav Chavan | 11th Aug, 2014, 11:54: AM
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