5 moles of an idealgas expands isothermally from a pressure of 10atm to 2atm at 300k.What is the largest mass which can be lifted through a height of 1m in this expansion ? plzz explain the answer in detail

Asked by TVISHA Bhatt | 10th Aug, 2014, 06:12: PM

Expert Answer:

Solution:
 
 

Work done is given by,

w= -nRT ln (p1/p2)

     = -5 mol (8.314 JK-1 mol-1)(300K) ln(10atm/2atm)

     = -20.075x103J

Let M be the mass which can be lifted through a height of 1m.

Work done in lifting the mass = Mgh= M x 9.81ms-2 x 1m

                    M X 9.81 X 1 X m2s-2 = 20.075 x 103J

                       M = 2046 kg

Answered by Vaibhav Chavan | 11th Aug, 2014, 11:54: AM