CBSE Class 11-science Answered
what will be the answer
Asked by saranyachakraborty2007 | 25 Apr, 2024, 05:23: AM
Expert Answer
Dear Student,
The minimum energy required to overcome the attractive forces between an electron and the surface of silver (Ag metal)
= 5.52 × 10-19 J
Wavelength λ = 360 Ao
Maximum Kinetic Energy of the electron ejected out from silver which is being exposed to UV light =?
Energy absorbed = hc / λ
= 5.52 × 10-11 erg
or 5.5 × 10-18 J (1 erg = 10-7 J)
The energy of photon = Work function + Kinetic energy
So, Kinetic energy = (5.52 ×10-18 J) - (5.52 × 10-19 J) = 49.68 ×10-19 J
Answered by | 26 Apr, 2024, 10:23: AM
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