CBSE Class 11-science Answered
chemistry atomicstructure
![question image](http://images.topperlearning.com/topper/new-ate/top_mob16002737285362179846983aab1-0a48-4947-b515-eb1ee42efb85.jpg)
Asked by muramshettyaashrith218 | 16 Sep, 2020, 21:58: PM
De-Broglie wave length associated with a particle can be calculated by-
![straight p equals mv
straight p equals 1 cross times 10 to the power of negative 6 end exponent cross times 1
straight p equals 10 to the power of negative 6 end exponent Kgm divided by straight s
straight lambda equals straight h over straight p
straight lambda equals fraction numerator 6.624 cross times 10 to the power of negative 34 end exponent over denominator 10 to the power of negative 6 end exponent end fraction equals 6.624 cross times 10 to the power of negative 28 end exponent straight m](https://images.topperlearning.com/topper/tinymce/cache/838d7efd934d2c3a34f381e790034877.png)
Answered by Ravi | 23 Sep, 2020, 21:07: PM
Concept Videos
CBSE 11-science - Chemistry
Asked by sheeltahiliani | 23 May, 2024, 11:58: AM
CBSE 11-science - Chemistry
Asked by saranyachakraborty2007 | 25 Apr, 2024, 05:23: AM
CBSE 11-science - Chemistry
Asked by habibakhatoon112 | 15 Jul, 2022, 21:14: PM
CBSE 11-science - Chemistry
Asked by akankhyapradhan123 | 22 Oct, 2021, 19:29: PM
CBSE 11-science - Chemistry
Asked by kusumghosh71 | 21 Aug, 2021, 10:59: AM
CBSE 11-science - Chemistry
Asked by muramshettyaashrith218 | 16 Sep, 2020, 21:58: PM
CBSE 11-science - Chemistry
Asked by nandanappillai | 21 May, 2020, 13:08: PM
CBSE 11-science - Chemistry
Asked by rajarage18 | 23 Jan, 2020, 20:00: PM
CBSE 11-science - Chemistry
Asked by kuldeepsingh33087 | 27 Jul, 2019, 11:35: AM
CBSE 11-science - Chemistry
Asked by vijaykumartecno348 | 06 Jul, 2019, 21:26: PM