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a photon of 3000 Angstrom is absorbed by a gas and then re-elected as two photons. One photon is red 7600  Angstrom  .  What wavelength of other photon?  Here I am knowing solution but I am not able to understand that why we are using formula ( h*c/lambda of total =  h*c/lambda of 1 +h*c / lambda of 2 ) Please solve it
Asked by rajarage18 | 23 Jan, 2020, 08:00: PM

E =hc/λ Wavelength of 1st photon = λ1 Wavelength of 2nd photon = λ2 Energy conservation- E(Total) = E1 + E2 = Emitted energy hc/ λ  = hc/ λ1  + hc/ λ2  1/3000 = 1/7600 + 1/ λ2 1/ λ2  = (1/3000 – 1/7600)  λ2   = 4960 Angstrom = wavelength of second photon

Answered by Ravi | 24 Jan, 2020, 10:05: AM
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