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CBSE Class 10 Answered

Three small pumps and a large pump are filling a tank. Each small pump works at 2/3rd the rate of the large pump. If all four work at the same time, they should fill the tank in what fraction of the time it would have taken the large pump alone?
Asked by rushabh123 | 07 Feb, 2019, 10:33: PM
answered-by-expert Expert Answer
Let time taken by large pump to fill the tank = x hours.
since rating of small pump is 2/3 of large one, time taken by a small pump to fill the tank = (3/2)x hours
 
fraction of filling of tank in hour by large pump and three small pumps together = (1/x) + (3×3)/(2x) = 11/(2x)
 
hence time taken to fill the tank by all the pumps togeteher = (2x)/11
 
required fraction of time = 2/11
Answered by Thiyagarajan K | 08 Feb, 2019, 01:03: PM

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