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the poles AB and CD of different heights are standing vertically on the ground level from a point P on the line joining the foots of the pole on the level of ground the angle of elevation to the top of the pole are founded to be complementary the of the CD and the distance PD 20√3m and 20m respectively if the BP is 10m then find the length of AB and the distance AC between the tpo of the poles
Asked by mraniruddha03 | 02 Apr, 2024, 06:44: PM

Let AB and CD are poles .

Given distances of CP and CD are 20√3 m and 20 m respectively.

Hence ∠DPC = tan-1 [ 20 / (20 √3 ) ] = 30o.

It is given that ∠BPA and ∠DPC are complimentry .

Hence ∠BPA = 60o

If PB = 10 m , then AB = PB cos60 = 10 (1/2) m = 5 m

Answered by Thiyagarajan K | 02 Apr, 2024, 10:01: PM

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