CBSE Class 10 Answered
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Asked by arindeep.singh | 10 Sep, 2020, 19:04: PM
Given: sec theta + tan theta = p
TO find: sin theta
![Let space secθ space plus thin space tanθ space equals space straight p space... space left parenthesis straight i right parenthesis
sec squared straight theta minus tan squared straight theta equals 1
rightwards double arrow open parentheses secθ plus tanθ space close parentheses open parentheses secθ minus tanθ space close parentheses equals 1
rightwards double arrow secθ minus tanθ equals 1 over straight p... left parenthesis ii right parenthesis
Adding space left parenthesis straight i right parenthesis space and space left parenthesis ii right parenthesis comma space we space get
secθ equals fraction numerator straight p squared plus 1 over denominator 2 straight p end fraction rightwards double arrow cosθ equals fraction numerator 2 straight p over denominator 1 plus straight p squared end fraction
rightwards double arrow sinθ equals square root of 1 minus cos squared straight theta end root equals square root of 1 minus fraction numerator 2 straight p over denominator open parentheses 1 plus straight p squared close parentheses squared end fraction end root equals fraction numerator 1 minus straight p squared over denominator 1 plus straight p squared end fraction](https://images.topperlearning.com/topper/tinymce/cache/d20bcc66c35ada2fc51abd4913d3458f.png)
Answered by Renu Varma | 10 Sep, 2020, 19:48: PM
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