CBSE Class 10 Maths Introduction to Trigonometry
cos2 x - sin2 x can be written as
- tan15° + tan30° + tan15° ×tan30°=1
- Given that sin tita =a/b,then tan tita is equal to
- (1+tanA+secA) (1+cotA-cosecA)=?
- Proove that (CotA+CosecA-1)/(CotA-CosecA+1) = (1+CosA)/SinA
- prove that cos theta by 1-tan theta+sin theta by 1- cot theta equals to sin theta+ cos theta
- Cosec(theta) - cot(theta) = alpha then cosec(theta)+ cot( alpha)=?
- (1+secA)/secA = sin²A/(1-cosA)
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