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CBSE Class 10 Answered

The points M(3,4), N(-1,1),P(5,-1) are the vertices of triangle .Find the equation of the altitude of the triangle MNP drawn from point N. 
Asked by alishathapa076 | 30 Mar, 2019, 09:50: PM
answered-by-expert Expert Answer
Line passing through points (x1 , y1 ) and (x2 , y2) is given by,   begin mathsize 12px style y space minus space y subscript 1 space equals space fraction numerator y subscript 1 minus y subscript 2 over denominator x subscript 1 space minus space x subscript 2 subscript space end subscript end fraction open parentheses x space minus x subscript 1 close parentheses end style
Hence line passing through M(3,4) and P(5,-1) is,  begin mathsize 12px style y minus 4 space equals space fraction numerator 4 plus 1 over denominator 3 minus 5 end fraction open parentheses x space minus space 3 close parentheses space equals space open parentheses negative 5 over 2 close parentheses open parentheses x space minus space 3 close parentheses
end style .......................(1)
By simplifying the above eqn.(1), we get the equation of line passing through M and P is 5x+2y = 23
 
Hence Equation of the line perpendicular to line segment MP is,  2x-5y = k .........................(2)
 
 Since this perpendicular line passes through N(-1, 1) , we get,   k = 2(-1)-5(1) = -7
 
Hence equation of altitude is 2x-5y = -7
Answered by Thiyagarajan K | 30 Mar, 2019, 10:58: PM
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