CBSE Class 11-science Answered
Solve the following question:
Asked by nkrbasak | 29 Dec, 2011, 09:28: PM
Expert Answer
m= 2kg
coefficient of friction= 0.7 and F=?
as the block is at rest therefore, maximum force of static friction is
fs= coefficient of static friction x R
but R= mgcos30
fs =coefficient of static friction x mg cos30
=0.7x2x9.8cos30
=1.4x9.8x0.866
fs=11.9 N
but in yhis case , actual force of static friction cannot exceed the force due to gravity actind down the plane.
hence, actual force of static frictionis
= mgsin30= 2x9.8x0.5= 9.8 N
Answered by | 29 Dec, 2011, 09:52: PM
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