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a block of mass m is pulled along a horizontal smooth surface by a rope of mass m force p applied at one end of rope force which the rope exert on block is
Asked by rame123shshiv | 14 Nov, 2023, 06:18: AM

Fig.1 shows the system of mass m and rope of equal mass m is pulled by a force P .

The system is under accelerated motion with acceleration a due to the applied force P.

Fig.2 shows the free body diagram of rope and mass m showing the forces acting on rope and mass m .

F is the contact force between mass m and rope.

By Newton's third law , contact forces F acting on rope and mass are action-reaction pair ,
equal in magnitude and opposite in direction.

If we apply Newton's second law to rope , we get

...................(1)

If we apply Newton's second law to mass , we get

......................(2)

By adding eqn.(1) and (2) , we get ,  P = ( 2 m ) a

acceleration a = P / (2m)

Hence, we get contact force F from eqn.(2) , we get

F = P/2

Hence force exerted by rope on mass m is P/2
Answered by Thiyagarajan K | 14 Nov, 2023, 10:07: AM
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