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Two blocks of mass m=5kg and M=10 kg are connected by a string passing over a pulley B as shown. Another string connects the centre of the pulley B to the floor and passes over another pulley A as shown. An upward force F is applied at the centre of pulley A. Both the pulleys are massless. Find the acceleration of both the blocks if 1) F=100N.  2)F=500N
Asked by sakethrockzz007 | 14 Aug, 2023, 04:30: PM
Figure shows the free body diagrams of pulleys and blocks. F is applied force on pulley-A .

TA and TB are tension forces along the cables connected to pulley.

(mg) is weight  of block of mass m . (Mg) is weight of block of mass M.

In pulley-A , since pulley's mass is negligible , Tension forces TA balances the applied force.

Hence , we have,
. . . . . . . . . . . . . . . .  (1)
In pulley-B , we have

If applied force F = 100 N , then TB = 25 N , block of mass 5 kg moves downward with acceleration am

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Let aM be the acceleration of block of mass M

Hence acceleration aM is

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If applied force F = 500 N , then TB = 125 N .

Block of mass 5 kg moves upward with acceleration am .

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If aM is the acceleration of block of mass M , then we have

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