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CBSE - XI Science - Physics - Laws of Motion

Please solve the numerical

Asked by sukhmaneet 1st September 2009, 6:43 PM
Answered by Expert

Answer:

The component of weight parallel to  the inclined plane, W = mgsin30 = mg/2

The component of weight perpendicular to the inclined plane, i.e. normal reaction, W = mgcos30 = 3mg/2

The kinetic friction force = μW 

F = ma

W - μW = ma

mg/2 - μ3mg/2 = mg/4

1/2 - μ3/2 = 1/4

 μ = 1/23 = 0.28

Regards,

Team,

TopperLearning.

Answered by Expert 1st September 2009, 9:28 PM

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